9.5 Consider the differential amplifier specified in Problem 9.1 with G 2 grounded and vG1 =vid. Let vid be adjusted to the value that causes i D1 =0.09 mA and iD2 =0.07 mA. Find the corresponding values of vGS2, vS, vGS1, and hence vid. What is the difference output voltage vD2 −vD1? What is the voltage gain (vD2 − vD1)/vid? What value of vid results in i D1 =0.07 mA and iD2 =0.09 mA?