A hollow tube with a rectangular cross-section has external dimensions of 0.5 in by 1 in and a wall thickness of 0.05 in. Assume that the material is brass, for which the conductivity is  1 = 1.5×10 7 S/m. A DC current of 200 A is flowing through the outer part of the tube. Part a Calculate the potential difference across an L = 1 m length of the tube in the z direction. Part b Calculate the potential difference across the same tube that is filled with a second conducting material with conductivity  2 = 1.5×10 5 S/m.

A hollow tube with a rectangular cross-section has external dimensions of 0.5 in by 1 in and a

wall thickness of 0.05 in. Assume that the material is brass, for which the conductivity is

1

= 1.5×10

7

S/m. A DC current of 200 A is flowing through the outer part of the tube.

Part a

Calculate the potential difference across an L = 1 m length of the tube in the z direction.

Part b

Calculate the potential difference across the same tube that is filled with a second conducting

material with conductivity 

2

= 1.5×10

5

S/m.

Two perfectly-conducting spherical surfaces located the origin have radii rr

2

= 5.0 cm. A resistive medium with conductivity σ = 0.05 S/m exists between these conductive

surfaces. Given that the total current passing radially outward from surface 1 to surface 2 is

3.0 A, calculate the following quantities:

a. Potential difference V1

2

between the two conductors,

b. Total resistance R between the two conductors.

c. The electric field intensity 

, ,E r  inside the resistive medium.

A parallel plate capacitor is filled with a non-uniform dielectric characterized by

   

6 2

r

2 2 10z z    , where z is the height above the bottom plate. If the cross-sectional area is

S = 0.02 m

2

and d = 1 mm, calculate the total capacitance C.

img 5464 - A hollow tube with a rectangular cross-section has external dimensions of 0.5 in by 1 in and a  wall thickness of 0.05 in. Assume that the material is brass, for which the conductivity is   1  = 1.5×10 7  S/m. A DC current of 200 A is flowing through the outer part of the tube.  Part a  Calculate the potential difference across an L = 1 m length of the tube in the z direction.  Part b  Calculate the potential difference across the same tube that is filled with a second conducting  material with conductivity  2  = 1.5×10 5  S/m.img 5466 - A hollow tube with a rectangular cross-section has external dimensions of 0.5 in by 1 in and a  wall thickness of 0.05 in. Assume that the material is brass, for which the conductivity is   1  = 1.5×10 7  S/m. A DC current of 200 A is flowing through the outer part of the tube.  Part a  Calculate the potential difference across an L = 1 m length of the tube in the z direction.  Part b  Calculate the potential difference across the same tube that is filled with a second conducting  material with conductivity  2  = 1.5×10 5  S/m.img 5469 - A hollow tube with a rectangular cross-section has external dimensions of 0.5 in by 1 in and a  wall thickness of 0.05 in. Assume that the material is brass, for which the conductivity is   1  = 1.5×10 7  S/m. A DC current of 200 A is flowing through the outer part of the tube.  Part a  Calculate the potential difference across an L = 1 m length of the tube in the z direction.  Part b  Calculate the potential difference across the same tube that is filled with a second conducting  material with conductivity  2  = 1.5×10 5  S/m.fully solved with 100% correct solutions

This content is for Premium members only.
sign up for premium and access unlimited solutions for a month at just 5$(not renewed automatically)


images - A hollow tube with a rectangular cross-section has external dimensions of 0.5 in by 1 in and a  wall thickness of 0.05 in. Assume that the material is brass, for which the conductivity is   1  = 1.5×10 7  S/m. A DC current of 200 A is flowing through the outer part of the tube.  Part a  Calculate the potential difference across an L = 1 m length of the tube in the z direction.  Part b  Calculate the potential difference across the same tube that is filled with a second conducting  material with conductivity  2  = 1.5×10 5  S/m.

already a member please login


7   +   9   =  

No questions found.