In the following circuit, a load z_load is connected in series with a resistor and a voltage source. If v_in(t) = 10 squareroot 2 cos(120 pi t) and z_load = 4 + j10, find the load average power and the reactive power absorbed by the load. (1) P_ave, = 2 W, Q = 5 VAR. (2) P_ave = 4 W, Q = 10 VAR (3) P_ave = 2 W, Q = -5 VAR. (4) P_ave = 4 W, Q = -10 VAR. (5) P_ave = 2 squareroot 2 W, Q = 5 squareroot 2 VAR. (6) P_ave = 4 squareroot 2 W, Q = 10 squareroot 2 VAR (8) P_ave = 4 squareroot 2 W, Q = -10 squareroot 2 VAR. Answer (1)

7.6 - In the following circuit, a load z_load is connected in series with a resistor and a voltage source. If v_in(t) = 10 squareroot 2 cos(120 pi t) and z_load = 4 + j10, find the load average power and the reactive power absorbed by the load. (1) P_ave, = 2 W, Q = 5 VAR. (2) P_ave = 4 W, Q = 10 VAR (3) P_ave = 2 W, Q = -5 VAR. (4) P_ave = 4 W, Q = -10 VAR. (5) P_ave = 2 squareroot 2 W, Q = 5 squareroot 2 VAR. (6) P_ave = 4 squareroot 2 W, Q = 10 squareroot 2 VAR (8) P_ave = 4 squareroot 2 W, Q = -10 squareroot 2 VAR. Answer (1)

This content is for Premium members only.
sign up for premium and access unlimited solutions for a month at just 5$(not renewed automatically)


images - In the following circuit, a load z_load is connected in series with a resistor and a voltage source. If v_in(t) = 10 squareroot 2 cos(120 pi t) and z_load = 4 + j10, find the load average power and the reactive power absorbed by the load. (1) P_ave, = 2 W, Q = 5 VAR. (2) P_ave = 4 W, Q = 10 VAR (3) P_ave = 2 W, Q = -5 VAR. (4) P_ave = 4 W, Q = -10 VAR. (5) P_ave = 2 squareroot 2 W, Q = 5 squareroot 2 VAR. (6) P_ave = 4 squareroot 2 W, Q = 10 squareroot 2 VAR (8) P_ave = 4 squareroot 2 W, Q = -10 squareroot 2 VAR. Answer (1)

already a member please login